(x^2-2x+4)(3x^2-7)=0

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Solution for (x^2-2x+4)(3x^2-7)=0 equation: 


Simplifying
(x2 + -2x + 4)(3x2 + -7) = 0

Reorder the terms:
(4 + -2x + x2)(3x2 + -7) = 0

Reorder the terms:
(4 + -2x + x2)(-7 + 3x2) = 0

Multiply (4 + -2x + x2) * (-7 + 3x2)
(4(-7 + 3x2) + -2x * (-7 + 3x2) + x2(-7 + 3x2)) = 0
((-7 * 4 + 3x2 * 4) + -2x * (-7 + 3x2) + x2(-7 + 3x2)) = 0
((-28 + 12x2) + -2x * (-7 + 3x2) + x2(-7 + 3x2)) = 0
(-28 + 12x2 + (-7 * -2x + 3x2 * -2x) + x2(-7 + 3x2)) = 0
(-28 + 12x2 + (14x + -6x3) + x2(-7 + 3x2)) = 0
(-28 + 12x2 + 14x + -6x3 + (-7 * x2 + 3x2 * x2)) = 0
(-28 + 12x2 + 14x + -6x3 + (-7x2 + 3x4)) = 0

Reorder the terms:
(-28 + 14x + 12x2 + -7x2 + -6x3 + 3x4) = 0

Combine like terms: 12x2 + -7x2 = 5x2
(-28 + 14x + 5x2 + -6x3 + 3x4) = 0

Solving
-28 + 14x + 5x2 + -6x3 + 3x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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